document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429877>Question 429877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $6000 is invested. Part at 8% and the remainder at 14%. How much is invested at each rate if the annual interest is $780 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298552 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount invested at 14%<BR>\n" );
document.write( "Then 6000-x = the amount invested at 8%<BR>\n" );
document.write( "The total interest earned is $780.<BR>\n" );
document.write( "So we can write<BR>\n" );
document.write( "0.14x + 0.08(6000-x) = 780<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "0.14x - 0.08x + 480 = 780 -> x = 300/0.06 = $5000<BR>\n" );
document.write( "Therefore the amount invested at 8% interest = 6000 - 5000 = $1000 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );