document.write( "Question 429870: cos(x+(π/2))-cos(2x)=0 \n" ); document.write( "
Algebra.Com's Answer #298549 by Gogonati(855)\"\" \"About 
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Solution:From the trigonometry we know that: \"cos2x=%28cos%28x%29%29%5E2-%28sin%28x%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( " \"%28cos%28x%29%29%5E2=1-%28sin%28x%29%29%5E2\", and cos(90+x)=-sin(x). Now we write:\r
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\n" ); document.write( "\n" ); document.write( "\"2%28sin%28x%29%29%5E2-sin%28x%29-1=0\", substitute six=a and rewrite the equation:\r
\n" ); document.write( "\n" ); document.write( "\"2a%5E2-a-1=0\", which is a quadratic equation. Solve this equation:\r
\n" ); document.write( "\n" ); document.write( "There are two roots: a=1 and a=-1/2, thus we have: sin(x)=1 and sin(x)=-12\r
\n" ); document.write( "\n" ); document.write( "Solve now these two trigonometric equations and find:\r
\n" ); document.write( "\n" ); document.write( "x=2n*\"pi\"+ \"pi\"/2, \r
\n" ); document.write( "\n" ); document.write( "x=2n*\"pi\"-\"pi\"/6, and x=2n*\"pi\"+\"7pi\"/6\r
\n" ); document.write( "\n" ); document.write( "Done.\r
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