document.write( "Question 429773: How do I find out what the Vertical Asymptote is for this function:
\n" ); document.write( "2x^2-6/x^3-8?
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Algebra.Com's Answer #298530 by richard1234(7193) $\"\"$ $\"About$

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A vertical asymptote occurs when the denominator is zero and the numerator is nonzero. Here, we want $\"x%5E3+-+8+=+0\"$ --> $\"x%5E3+=+8\"$ . The only real solution is x=2. The numerator is equal to $\"2%282%5E2%29+-+6+=+2+%3C%3E+0\"$ so we can say that x=2 produces a vertical asymptote. \n" ); document.write( "

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