document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429834>Question 429834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 64. Twice the smaller number is 10 less than the larger number. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298517 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"The sum of two numbers is 64. Twice the smaller number is 10 less than the larger number. Find the numbers.\"\r<BR>\n" );
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document.write( "x = one number<BR>\n" );
document.write( "64 - x = other number {sum of two numbers is 64}\r<BR>\n" );
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document.write( "2x = 64 - x - 10 {twice smaller is ten less than larger}<BR>\n" );
document.write( "2x = 54 - x {combined like terms}<BR>\n" );
document.write( "3x = 54 {added x to both sides}<BR>\n" );
document.write( "x = 18 {divided both sides by 3}<BR>\n" );
document.write( "64 - x = 46 {substituted 18, in for x, into 64 - x}\r<BR>\n" );
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document.write( "the two numbers are 18 and 46<BR>\n" );
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