document.write( "Question 429806: a 9 inch candle burns at a rate of 1/3 inches per hour.
\n" ); document.write( "a. write an equation in slope intercept form of this situation.
\n" ); document.write( "b.how many hours will it take for the candle to be completely burned?
\n" ); document.write( "c.how long will the candle be after burning for 6 hours?
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Algebra.Com's Answer #298513 by ankor@dixie-net.com(22740)\"\" \"About 
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a 9 inch candle burns at a rate of 1/3 inches per hour.
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\n" ); document.write( "a. write an equation in slope intercept form of this situation.
\n" ); document.write( "let t = no. of hrs
\n" ); document.write( "f(t) = length of the candle in inches
\n" ); document.write( "f(t) = -\"1%2F3\"t + 9
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\n" ); document.write( "b.how many hours will it take for the candle to be completely burned?
\n" ); document.write( "f(t) = 0 inches, so we have
\n" ); document.write( "-\"1%2F3\"t + 9 = 0
\n" ); document.write( "-\"1%2F3\"t = -9
\n" ); document.write( "Multiply both sides by -3
\n" ); document.write( "t = 27 hrs to be completely burned
\n" ); document.write( ":
\n" ); document.write( "c.how long will the candle be after burning for 6 hours?
\n" ); document.write( "t = 6
\n" ); document.write( "f(6) = -\"1%2F3\"(6) + 9
\n" ); document.write( "f(6) = -2 + 9
\n" ); document.write( "f(6) = 7 inches after 6 hrs
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