document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429791>Question 429791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a trapezoid with 45 degree base angles and bases 17 and 23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298499 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Due to the base angle of 45 degrees, the height of the (isosceles) triangle would be (23-17)/2 = 3. Hence the area of the trapezoid is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2F2%29%2A%2817%2B23%29+=+3%2A20+=+60 ALIGN=MIDDLE  ALT=\"%283%2F2%29%2A%2817%2B23%29+=+3%2A20+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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