document.write( "Question 429770: I need help with a couple of fraction. I actually figured the others by myself which means I'm getting better. Simplify the complex fraction by any method.\r
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document.write( "1/3y + 1/6y / 1/2y + 3/4y\r
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document.write( "2/y+4 / 3/y-4 - 1/y^2 - 16 \n" );
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Algebra.Com's Answer #298476 by stanbon(75887) ![]() You can put this solution on YOUR website! [1/3y + 1/6y] / [1/2y + 3/4y] \n" ); document.write( "--- \n" ); document.write( "= [(2/6)y + (1/6)y] / [(2/4)y + (3/4)y] \n" ); document.write( "----- \n" ); document.write( "= [(3/6)y] / [(5/4)y] \n" ); document.write( "---- \n" ); document.write( "Invert and multiply: \n" ); document.write( "= [(3y/6)] * [(4/5y)] \n" ); document.write( "------------- \n" ); document.write( "= [12y/30y] \n" ); document.write( "--- \n" ); document.write( "= (2/5) \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( "[2/(y+4)] / [(3/(y-4)) - (1/(y^2 - 16))] \n" ); document.write( "--- \n" ); document.write( "[2/(y+4)] /[(3(y+4)/(y^2-16)) - 1/(y^2-16)] \n" ); document.write( "--- \n" ); document.write( "= [2/(y+4)] / [(3y+12-1)/(y^2-16)] \n" ); document.write( "---- \n" ); document.write( "= [2/(y+4)] \n" ); document.write( "--- \n" ); document.write( "Cancel (y+4) from numerator and denominator to get: \n" ); document.write( "------------------ \n" ); document.write( "= [2(y-4)]/(3y+11) \n" ); document.write( "===================== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |