document.write( "Question 429770: I need help with a couple of fraction. I actually figured the others by myself which means I'm getting better. Simplify the complex fraction by any method.\r
\n" ); document.write( "\n" ); document.write( "1/3y + 1/6y / 1/2y + 3/4y\r
\n" ); document.write( "\n" ); document.write( "2/y+4 / 3/y-4 - 1/y^2 - 16
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Algebra.Com's Answer #298476 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
[1/3y + 1/6y] / [1/2y + 3/4y]
\n" ); document.write( "---
\n" ); document.write( "= [(2/6)y + (1/6)y] / [(2/4)y + (3/4)y]
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\n" ); document.write( "= [(3/6)y] / [(5/4)y]
\n" ); document.write( "----
\n" ); document.write( "Invert and multiply:
\n" ); document.write( "= [(3y/6)] * [(4/5y)]
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\n" ); document.write( "= [12y/30y]
\n" ); document.write( "---
\n" ); document.write( "= (2/5)
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\n" ); document.write( "[2/(y+4)] / [(3/(y-4)) - (1/(y^2 - 16))]
\n" ); document.write( "---
\n" ); document.write( "[2/(y+4)] /[(3(y+4)/(y^2-16)) - 1/(y^2-16)]
\n" ); document.write( "---
\n" ); document.write( "= [2/(y+4)] / [(3y+12-1)/(y^2-16)]
\n" ); document.write( "----
\n" ); document.write( "= [2/(y+4)]
\n" ); document.write( "---
\n" ); document.write( "Cancel (y+4) from numerator and denominator to get:
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\n" ); document.write( "= [2(y-4)]/(3y+11)
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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