document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429725>Question 429725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 120 cm. The length of the diagonol is 9 cm longer than the width. What are the dimensions of the rectangle? You need to use algebra! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298460 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:Let x cm the width, then the diagonal is x+9 cm, and the length of rectangle, using Pythagorean theorem will be:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L%5E2=%28x%2B9%29%5E2-x%5E2=x%5E2%2B18x%2B81-x%5E2=18x%2B81 ALIGN=MIDDLE  ALT=\"L%5E2=%28x%2B9%29%5E2-x%5E2=x%5E2%2B18x%2B81-x%5E2=18x%2B81\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=sqrt%2818x%2B81%29 ALIGN=MIDDLE  ALT=\"L=sqrt%2818x%2B81%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The perimeter of rectangle is:2L+2W=120 => L+W=60 Write the equation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2818x%2B81%29%2Bx=60 ALIGN=MIDDLE  ALT=\"sqrt%2818x%2B81%29%2Bx=60\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve the equation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2818x%2B81%29=60-x ALIGN=MIDDLE  ALT=\"sqrt%2818x%2B81%29=60-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, squaring both sides have:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18x%2B81=x%5E2-120x%2B3600 ALIGN=MIDDLE  ALT=\"18x%2B81=x%5E2-120x%2B3600\"   DISABLED_style= \"max-width:90%; height:auto;\" >, set equation to zero.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-138x%2B3519=0 ALIGN=MIDDLE  ALT=\"x%5E2-138x%2B3519=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, solve the quadratic equation.\r<BR>\n" );
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document.write( "The roots that satisfy our problem is L=33.75 cm and W=26.34 cm.\r<BR>\n" );
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document.write( "Done.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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