document.write( "Question 429657: How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 6 gallons of 30% alcohol solution?
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Algebra.Com's Answer #298414 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Mixture to be 6 gallons of 30% alcohol solution
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document.write( "Let x and (6-x)represent the amount of the 40% and 25% respectively
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document.write( "Question states***
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document.write( "  Mixing
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document.write( " .40x + .25(6-x) = .30*6gal
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document.write( "       .15x = .05*6
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document.write( "          x = 2gal of 40% solution and 4gal of 25% ssolution\r
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document.write( "CHECKING our Answer***
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document.write( "   .4*2 + .25*4 = .8 + 1 = .3*6 = 1.8gal \n" );
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