document.write( "Question 429637: The revenue function in terms of the number of
\n" ); document.write( "units sold ,x, is given as
\n" ); document.write( "R = 270x-0.1x^2
\n" ); document.write( "where R is the total revenue in dollars. Find the number of units
\n" ); document.write( "sold x that produces a maximum revenue?
\n" ); document.write( "Your answer is x =
\n" ); document.write( "what is the maximum revenue = \n" ); document.write( "

Algebra.Com's Answer #298408 by htmentor(1343) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"R+=+270x-0.1x%5E2\"$
\n" ); document.write( "The function reaches a maximum where the derivative is equal to 0.
\n" ); document.write( " $\"dR%2Fdx+=+0+=+270+-+0.2x\"$
\n" ); document.write( "Solving for x gives x = -270/-0.2 = 1350
\n" ); document.write( "So the number of units which produces the maximum revenue = 1350
\n" ); document.write( "Substituting this value in the original equation gives the revenue:
\n" ); document.write( " $\"R+=+270%281350%29+-+0.1%281350%29%5E2\"$
\n" ); document.write( "This gives R = $182,250
\n" ); document.write( "The function looks like this:
\n" ); document.write( " $\"graph%28600%2C500%2C-4000%2C4000%2C-200000%2C200000%2C270x-0.1x%5E2%29\"$ \n" ); document.write( "

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