document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429487>Question 429487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-1\7=3x\2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298382 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 2x-1/7=3x/2, then we need to multiply both sides of the equation by 14, which is the least common multiple, which gives us:\r<BR>\n" );
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document.write( "14(2x-1/7)=14(3x/2)<BR>\n" );
document.write( "28x-2=21x<BR>\n" );
document.write( "7x=2<BR>\n" );
document.write( "x=2/7 </SPAN>\n" );
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