document.write( "Question 429579: The length of a rectangle is 3 ft less than twice its width, and the area of the rectangle is 44 ft^2 . \r
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document.write( "Find the dimensions of the rectangle \n" );
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Algebra.Com's Answer #298378 by John10(297) You can put this solution on YOUR website! The length of a rectangle is 3 ft less than twice its width, and the area of the rectangle is 44 ft^2 . \r \n" ); document.write( "\n" ); document.write( "Find the dimensions of the rectangle\r \n" ); document.write( "\n" ); document.write( " ------------------------------------\r \n" ); document.write( "\n" ); document.write( "L = 3 + 2W \n" ); document.write( "A = L * W = 44\r \n" ); document.write( "\n" ); document.write( "Solve above system to find L and W\r \n" ); document.write( "\n" ); document.write( "Hint: W = 4 and L = 11\r \n" ); document.write( "\n" ); document.write( "Check: A = L*W = 4 *11 = 44\r \n" ); document.write( "\n" ); document.write( "John10 \n" ); document.write( " |