document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429539>Question 429539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If twice a number added to 3 is divided by the number 9, the result is five thirds.Find the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298322 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If twice a number added to 3 is divided by the number 9, the result is five thirds.Find the number?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Let the number be \"x\":<BR>\n" );
document.write( "Solve:<BR>\n" );
document.write( "(2x+3)/9 = 5/3<BR>\n" );
document.write( "Cross-multiply:<BR>\n" );
document.write( "3(2x+3) = 45<BR>\n" );
document.write( "6x+9 = 45<BR>\n" );
document.write( "6x = 36<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );