document.write( "Question 429528: Three years ago, Joe's age was 1 year more than twice Karen's. Six years from now, his age will be 10 years more than half her age. how old is Joe? \n" ); document.write( "
Algebra.Com's Answer #298310 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Three years ago, Joe's age was 1 year more than twice Karen's. Six years from now, his age will be 10 years more than half her age. how old is Joe?
\n" ); document.write( "-------
\n" ); document.write( "Equations:
\n" ); document.write( "(j-3) = 2(k-3)+1
\n" ); document.write( "(j+6) = (1/2)(k+6)+10
\n" ); document.write( "-----
\n" ); document.write( "Rearrange the 1st equation:
\n" ); document.write( "j-3 = 2k-6+1
\n" ); document.write( "j-3 = 2k-5
\n" ); document.write( "j = 2k-2
\n" ); document.write( "---
\n" ); document.write( "Substitute into the 2nd equation and solve for \"k\":
\n" ); document.write( "(2k-2+6) = (1/2)(k + 6) + 10
\n" ); document.write( "Multiply thru by 2:
\n" ); document.write( "2(2k+4) = k+6+20
\n" ); document.write( "4k+8 = k+26
\n" ); document.write( "3k = 18
\n" ); document.write( "k = 6 (Karen's age now)
\n" ); document.write( "---
\n" ); document.write( "Solve for \"j\":
\n" ); document.write( "j = 2k-2
\n" ); document.write( "j = 12-2
\n" ); document.write( "j = 10 (Joe's age now)
\n" ); document.write( "===========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============
\n" ); document.write( " \n" ); document.write( "
\n" );