document.write( "Question 429501: A hotel has 200 rooms. Those with kitchen facilities rent for $100 per night and those without kitchen facilities rent for $80 per night. On a night when the hotel was completely occupied, revenues were $17,000. How many of each type of room does the hotel have? \n" ); document.write( "
Algebra.Com's Answer #298294 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
rooms with kitchen x
\n" ); document.write( "rooms without kitchen ------------ y
\n" ); document.write( "x+y=200 .............1
\n" ); document.write( "100x+80 y=17000 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 80
\n" ); document.write( "Multiply (2) by -1
\n" ); document.write( "80x+5y=16000
\n" ); document.write( "-100x+2 y=-17000
\n" ); document.write( "Add the two equations
\n" ); document.write( "-20x=-1000
\n" ); document.write( "/-20
\n" ); document.write( "x=50 rooms with kitchen
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "
\n" ); document.write( "x+y=200
\n" ); document.write( "50 + y=200
\n" ); document.write( "y=150 rooms without kitchen
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );