document.write( "Question 429422: The length of a rectangle is 4cm, longer than its width.
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document.write( "If the perimeter of the rectangle is 32cm , find its area.
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Algebra.Com's Answer #298286 by edjones(8007)![]() ![]() You can put this solution on YOUR website! L=w+4 \n" ); document.write( "2(L+w)=p \n" ); document.write( "2(w+4+w)=32 Substitute w+4 for L. \n" ); document.write( "2(2w+4)=32 \n" ); document.write( "4w+8=32 \n" ); document.write( "4w=24 \n" ); document.write( "w=6 \n" ); document.write( "L=10 \n" ); document.write( ". \n" ); document.write( "Lw=A \n" ); document.write( "10*6=60 cm^2 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |