document.write( "Question 429428: If X is a normal random variable with standard deviation 3.50, and if the probability that X is more than 10.83 is .1271, then what is the mean of X?
\n" ); document.write( "Please work out solution so I can see how the answer was achieved.\r
\n" ); document.write( "\n" ); document.write( "If X is a normal random variable with a standard deviation 3.50, and if the probability that X is less than 8.83 is .648, then what is the mean of X?
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Algebra.Com's Answer #298265 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"P%28z+=+%28X+-+mu%29%2F3.5+%3E+%2810.83+-+mu%29%2F3.5%29+=+0.1271\", or
\n" ); document.write( "\"P%28z+=+%28X+-+mu%29%2F3.5+%3C++%2810.83+-+mu%29%2F3.5%29+=+0.8729\"
\n" ); document.write( "==> \"%2810.83+-+mu%29%2F3.5+=+1.14\", approximately, from a table of standard normal values.
\n" ); document.write( "==> \"10.83+-+mu+=+3.99\"
\n" ); document.write( "==> \"mu+=+6.84\"
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