document.write( "Question 429443: PLEASE HELP im Stuck on this problem. Thank You\r
\n" ); document.write( "\n" ); document.write( "Let A, B, and C be subsets of a universal set U and suppose n(U) = 150, n(A) = 23, n(B) = 25, n(C) = 29, n(A ∩ B) = 8, n(A ∩ C) = 9, n(B ∩ C) = 14, and n(A ∩ B ∩ C) = 5\r
\n" ); document.write( "\n" ); document.write( "(a) n[A ∩ (B U C)]\r
\n" ); document.write( "\n" ); document.write( "(b) n[A ∩ (B U C)c]
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Algebra.Com's Answer #298259 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
(a) n(A ∩ (B U C)) = n((A ∩B) U (A ∩C))\r
\n" ); document.write( "\n" ); document.write( "= n(A ∩B) + n(A ∩C) - n(A ∩ B ∩ C)\r
\n" ); document.write( "\n" ); document.write( "= 8 + 9 - 5 = 12.\r
\n" ); document.write( "\n" ); document.write( "(b) \"B+U+C\" and \"%28B+U+C%29%5Ec\" are disjoint, hence so are A ∩ \"B+U+C\" and A ∩ \"%28B+U+C%29%5Ec\".
\n" ); document.write( "==> nA = n(A ∩ \"B+U+C\" ) + n(A ∩ \"%28B+U+C%29%5Ec\")
\n" ); document.write( "==> 23 = 12 + n(A ∩ \"%28B+U+C%29%5Ec\")
\n" ); document.write( "==> n(A ∩ \"%28B+U+C%29%5Ec\") = 11.
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