document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429436>Question 429436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fred Flinstones wheel from his car is 2 clubs wide and he diameter is 1.5 clubs. <BR>\n" );
document.write( "a) What is the surface area of the part that rolls on the road (Lateral surface area)?<BR>\n" );
document.write( "b) What is the total surface area of the inside of the wheel if the diameter of the axle is 1/2 club? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298251 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a.  Circumference is 2pir or pi*d<BR>\n" );
document.write( "It is 2 club wide so surface area=2club*3.14*1.5= 9.42 club ANS<BR>\n" );
document.write( "b I am not sure where the axle is. </SPAN>\n" );
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