document.write( "Question 429427: Convert the equation to polar form.
\n" ); document.write( " 5x=5y
\n" ); document.write( "i have already started the problem to:
\n" ); document.write( " 5(rcostheta)=5(rsintheta)\r
\n" ); document.write( "\n" ); document.write( "and don't where to go from there Please help me!
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Algebra.Com's Answer #298244 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
I presume the linear equation will have a strange polar representation.\r
\n" ); document.write( "\n" ); document.write( "From 5x = 5y we obtain x = y and \"r%2Acos%28theta%29+=+r%2Asin%28theta%29\". We wish to isolate r.\r
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\n" ); document.write( "\n" ); document.write( "Moving all terms to one side we get \"r%2Acos%28theta%29+-+r%2Asin%28theta%29+=+0\" --> \"r%28cos%28theta%29+-+sin%28theta%29%29+=+0\" and \"r+=+0%2F%28cos%28theta%29-sin%28theta%29%29\". What's interesting about this graph is that when \"cos%28theta%29+-+sin%28theta%29+=+0\" (\"theta+=+pi%2F4+%2B+k%2Api\"), we get an indeterminate form and r can equal anything. \"0%2F0\" can theoretically be equal to any number, which is why it is considered indeterminate instead of undefined.
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