document.write( "Question 429347: A Ricoh copier can complete a job in 10 minutes. A xerox machine can do the same job in 12 minutes. A worker needs a job completed in 5 minutes. If both copiers work on the job at the same time, will the worker have the job done in time? Explain with work shown. \n" ); document.write( "

Algebra.Com's Answer #298223 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A Ricoh copier can complete a job in 10 minutes.
\n" ); document.write( " A xerox machine can do the same job in 12 minutes.
\n" ); document.write( "A worker needs a job completed in 5 minutes.
\n" ); document.write( "If both copiers work on the job at the same time, will the worker have the job done in time?
\n" ); document.write( " Explain with work shown.
\n" ); document.write( ":
\n" ); document.write( "Let t = time required with both copiers operating
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "Each copier will do a fraction of the job, the two factions must add up to 1
\n" ); document.write( " $\"t%2F10\"$ + $\"t%2F12\"$ = 1
\n" ); document.write( "To clear the denominators, multiply by 60, results:
\n" ); document.write( "6t + 5t = 60
\n" ); document.write( "11t = 60
\n" ); document.write( "t = $\"60%2F11\"$
\n" ); document.write( "t = 5.45 min, so not quite \n" ); document.write( "

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