document.write( "Question 429287: Two cars heading in same direction, 300 ft apart. One behind is traveling 53 mph, one in front is traveling 40 mph. How many seconds until they hit? What if the front one is traveling 10 mph? \n" ); document.write( "

Algebra.Com's Answer #298218 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"d\"$ = distance front car has to go
\n" ); document.write( "Let $\"t\"$ = time for them to meet
\n" ); document.write( "equation for 40 mi/hr car
\n" ); document.write( "(1) $\"d+=+40t\"$
\n" ); document.write( "equation for 53 mi/hr car
\n" ); document.write( "(2) $\"d+%2B+300%2F5280+=+53t+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"40t+%2B+300%2F5280+=+53t+\"$
\n" ); document.write( " $\"+13t+=+300%2F5280+\"$
\n" ); document.write( " $\"+t+=+.0568%2F13+\"$
\n" ); document.write( " $\"+t+=+.00437+\"$ hrs
\n" ); document.write( " $\"+t+=+.00437+%2A+60%2A60+=+15.73+\"$ hrs x min/hr x sec/min
\n" ); document.write( "They hit in 15.73 sec
\n" ); document.write( "--------------------------
\n" ); document.write( "If the front car goes 10 mi/hr
\n" ); document.write( "(1) $\"+d+=+10t+\"$
\n" ); document.write( "(2) $\"d+%2B+300%2F5280+=+53t+\"$
\n" ); document.write( "(2) $\"10t+%2B+300%2F5280+=+53t+\"$
\n" ); document.write( " $\"+43t+=+.0568+\"$
\n" ); document.write( " $\"+t+=+.00132+\"$ hrs
\n" ); document.write( " $\"+t+=+.00132+%2A+60+%2A+60+=+4.757+\"$ sec
\n" ); document.write( "They hit in 4.757 sec \n" ); document.write( "

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