document.write( "Question 429233: The bowling alley on Wedge Street charges $5.00 for shoe rental plus $1.50 per game.The bowling alley on Lawrence Street charges $3.00 for shoe rental plus $2.00 per game. If one person rents a pair of shoes to bowl, how many games should they bowl to make the bowling alley on Wedge Street cheaper than the bowling alley on Lawrence Street \n" ); document.write( "
Algebra.Com's Answer #298188 by John10(297)![]() ![]() You can put this solution on YOUR website! The bowling alley on Wedge Street charges $5.00 for shoe rental plus $1.50 per game.The bowling alley on Lawrence Street charges $3.00 for shoe rental plus $2.00 per game. If one person rents a pair of shoes to bowl, how many games should they bowl to make the bowling alley on Wedge Street cheaper than the bowling alley on Lawrence Street. \n" ); document.write( "Let g be the number of bowling games: \n" ); document.write( "Wedge Street: C = 1.50g + 5.00 \n" ); document.write( "Lawrence Street: C = 2.00g + 3.00\r \n" ); document.write( "\n" ); document.write( "If Wedge street is cheaper than Lawrence street then \n" ); document.write( "1.5g + 5 < 2g + 3 \n" ); document.write( "1.5g - 2g < 3 - 5 \n" ); document.write( "-0.5g < -2 \n" ); document.write( "g > (-2)/(-0.5) \n" ); document.write( "g > 4\r \n" ); document.write( "\n" ); document.write( "Thus that person must play more than 4 bowling games, so the Wedge Street is cheaper than Lawrence.\r \n" ); document.write( "\n" ); document.write( "There you go! \n" ); document.write( " |