document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45013>Question 45013</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation In(x+5)-In(3)=In(x-3).  My answer is 7 could that be right.  thanks for any help given. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29817 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(x + 5) - ln(3) = ln(x - 3)<BR>\n" );
document.write( "ln((x + 5)/3) = ln(x - 3)<BR>\n" );
document.write( "(x + 5)/3 = x - 3<BR>\n" );
document.write( "x + 5 = 3x - 9<BR>\n" );
document.write( "14 = 2x<BR>\n" );
document.write( "7 = x </SPAN>\n" );
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