document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429103>Question 429103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how long will it take a bus traveling at 60 miles per hour to overtake a car traveling at 40 mph if the car had a 1.5 hour head start? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298155 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If our bus is traveling at 60 mph, then X/60 is the amount of the distance covered by the bus before the two vehicles meet, per hour.  Similarly, X/40 is the amount of the converging distance covered by the car.  Therefore, we have:\r<BR>\n" );
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document.write( "X/60 + 1.5 = X/40\r<BR>\n" );
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document.write( "Multiplying through by 240, we get;\r<BR>\n" );
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document.write( "4X + 360 = 6X<BR>\n" );
document.write( "360 = 2X<BR>\n" );
document.write( "180 = X\r<BR>\n" );
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document.write( "Since our distance is 180 miles, the amount of time traveled by the bus is 180 miles / 60 miles/hour, or 3 hours.  The bus has been traveling for 3 hours, the car has been traveling for 4.5 hours:\r<BR>\n" );
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document.write( "180=180.<BR>\n" );
document.write( " </SPAN>\n" );
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