document.write( "Question 429152: an investment of $1500 paid interest of $45 during a certain period. How much interest would an investment of $2000 invested at the same rate for the same length of time pay?
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\n" ); document.write( "I tried $1500 x n=$45.....thinking i could divide both sides by 45 to get the percent of interest but that didn't work. Could you please explain how to find the interest rate I think I can figure it out if i have that \n" ); document.write( "

Algebra.Com's Answer #298136 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "investment of $1500 paid interest of $45 during a certain period
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document.write( "Let x represent interest on an investment of $2000 invested similarly
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document.write( "Question sets Up the Proportion***
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document.write( "       | Cross Multiplying 
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document.write( "  1500x = 45*2000
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document.write( "      x = 45*2000/1500
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document.write( "      x = $60, interest on an investment of $2000 invested similarly\r
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document.write( "CHECKING our Answer***
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document.write( "  45/1500 = 60/2000 = 3/100 \n" );
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