document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=429092>Question 429092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 3^(4x+2) =9^(x-1) (Hint: Write both sides as a power of 3 and then match the powers.) \r<BR>\n" );
document.write( "\n" );
document.write( "I do not get this problem even with the hint. Please help. :) Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298122 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^(4x+2) =9^(x-1)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "3^(4x+2) = (3^2)^(x-1)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "3^(4x+2) = 3^(2x-2)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "4x+2 = 2x-2<BR>\n" );
document.write( "2x = -4<BR>\n" );
document.write( "x = -2<BR>\n" );
document.write( "=========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );