document.write( "Question 44997: 10/x - 12/x-3 + 4 = 0 \n" ); document.write( "
Algebra.Com's Answer #29811 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! 10(x(x-3))/x - 12(x(x-3))/x-3 + 4x(x-3) = 0 \n" ); document.write( "10x - 30 - 12x + 4x^2 - 12x = 0 \n" ); document.write( "4x^2 - 14x - 30 = 0 \n" ); document.write( "2x^2 - 7x - 15 = 0 \n" ); document.write( "2x^2 - 10x + 3x - 15 = 0 \n" ); document.write( "(2x^2 - 10x) + (3x - 15) = 0 \n" ); document.write( "2x(x - 5) + 3(x - 5) = 0 \n" ); document.write( "(2x + 3)(x - 5) = 0 \n" ); document.write( "x = -1.5 and x = 5 \n" ); document.write( " |