document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428966>Question 428966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimiter of a rectangle garden is 136feet the length of the garden is 4 feet less than 3 times the width write a system of equations that can be used to find the measure of the length and width of the rectangle let y be the measure of length and x be the measure of width <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #298075 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=298075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If X is the measure of width and Y the length, then our equations are:\r<BR>\n" );
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document.write( "Width=X<BR>\n" );
document.write( "Length=Y=3X-4\r<BR>\n" );
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document.write( "Since our perimeter is 136 ft.:\r<BR>\n" );
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document.write( "2(X)+2(3X-4)=136<BR>\n" );
document.write( "2X+6X-8=136<BR>\n" );
document.write( "8X=144<BR>\n" );
document.write( "X=18<BR>\n" );
document.write( "Y=3X-4=50 </SPAN>\n" );
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