document.write( "Question 429003: The area of a rectangle is 80 meters. the length is one more than three times the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #298060 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"The area of a rectangle is 80 meters. the length is one more than three times the width. Find the dimensions of the rectangle.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = width \n" ); document.write( "3x + 1 = length {length is one more than three times width}\r \n" ); document.write( "\n" ); document.write( "Area of a rectangle = length x width\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(3x + 1) = 80 {area is length x width} \n" ); document.write( "3x^2 + x = 80 {used distributive property} \n" ); document.write( "3x^2 + x - 80 + 0 {subtracted 80 from both sides to get into standard form} \n" ); document.write( "(3x + 16)(x - 5) = 0 {factored into two binomials} \n" ); document.write( "3x + 16 = 0 or x - 5 = 0 {set each factor equal to 0} \n" ); document.write( "3x = -16 or x = 5 {subtracted 16 and added 5, respectively} \n" ); document.write( "x = -16/3 or x = 5 {divided left equation by 3}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x cannot be negative, it is the width of a rectangle \n" ); document.write( "x = 5 \n" ); document.write( "3x + 1 = 16 {substituted 5, in for x, into 3x + 1}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = 5 m and length = 16 m \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " \n" ); document.write( " |