document.write( "Question 428979: 2x + y = 7
\n" ); document.write( "x + 3y = 1\r
\n" ); document.write( "\n" ); document.write( "use substitution to solve
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Algebra.Com's Answer #298044 by algebrahouse.com(1659)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "2x + y = 7
\n" ); document.write( "x + 3y = 1 ------> x = -3y + 1 {subtracted 3y from both sides}\r
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\n" ); document.write( "\n" ); document.write( "2(-3y + 1) + y = 7 {substituted -3y + 1, in for x, into top equation}
\n" ); document.write( "-6y + 2 + y = 7 {used distributive property}
\n" ); document.write( "-5y + 2 = 7 {combined like terms}
\n" ); document.write( "5y = 5 {subtracted 2 from both sides}
\n" ); document.write( "y = 1 {divided both sides by 5}\r
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\n" ); document.write( "\n" ); document.write( "x = -3y + 1
\n" ); document.write( "x = -3(1) + 1 {substituted 1, in for y, into x = -3y + 1}
\n" ); document.write( "x = -3 + 1 {multiplied -3 by 1}
\n" ); document.write( "x = -2 {combined like terms}\r
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\n" ); document.write( "\n" ); document.write( "x = -2 and y = 1
\n" ); document.write( "www.algebrahouse.com
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