document.write( "Question 850: The area of a square is 45 more square inches than its perimeter. Find the length of each side of the square. \n" ); document.write( "
Algebra.Com's Answer #298 by usyim88hk(158)\"\" \"About 
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let x be one side of the square:
\n" ); document.write( "x^2 is the area of the square
\n" ); document.write( "4x is the perimeter of the square
\n" ); document.write( "x^2 = 4x + 45 (Area is equal to the perimeter plus 45)
\n" ); document.write( "x^2-4x-45 = 4x+45-4x-45
\n" ); document.write( "x^2-4x-45 = 0 (now factor)
\n" ); document.write( "(x-9)(x+5) = 0
\n" ); document.write( "x = 9 or -5
\n" ); document.write( "Since length cannot be a negative number, -5 is not the answer, so the answer is 9
\n" ); document.write( "-------------------------------------------------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "9^2 = 4(9)+45
\n" ); document.write( "81 = 36+45
\n" ); document.write( "81=81 (Correct!!!) \n" ); document.write( "
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