document.write( "Question 428799: I would like to find out the equation for figuring out how long in seconds that it would take my train which is \"x\" feet long to completely pass through \"y\" length of railroad at a given rate speed which is \"z\" miles per hour.\r
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Algebra.Com's Answer #297968 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I would like to find out the equation for figuring out how long in seconds that it would take my train which is \"x\" feet long to completely pass through \"y\" length of railroad at a given rate speed which is \"z\" miles per hour.
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\n" ); document.write( "Assuming the train you are passing is not moving:
\n" ); document.write( "Assuming that \"passing\" means the time the front of
\n" ); document.write( "your train is parallel one end of the train till
\n" ); document.write( "the other end of your train is parallel to the
\n" ); document.write( "front end of the other train.
\n" ); document.write( "That distance is \"x+y\" feet
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\n" ); document.write( "time = distance/rate
\n" ); document.write( "time = (x+y)ft/z(miles/hour)
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\n" ); document.write( "Convert to seconds
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\n" ); document.write( "= [(x+y)/z](ft)
\n" ); document.write( "---
\n" ); document.write( "= [(x+y)/z][ft*60 sec./5280 ft]
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\n" ); document.write( "= [60(x+y)/5280z] sec.
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\n" ); document.write( "= [15(x+y)/2640z] sec.
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\n" ); document.write( "= [5(x+y)/880z] sec.
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\n" ); document.write( "= (1/176)[(x+y)/z] sec.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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