document.write( "Question 428724: The length of a rectangle is 5 m greater than the width. The area is 300 sq m. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #297961 by checkley79(3341) ![]() You can put this solution on YOUR website! L=W+5 \n" ); document.write( "A=LW \n" ); document.write( "300=(W+5)W \n" ); document.write( "300=W^2+5W \n" ); document.write( "W^2+5W-300=0 \n" ); document.write( "(W-15)(W+20)=0 \n" ); document.write( "W-15=0 \n" ); document.write( "W=15 AND. \n" ); document.write( "L=15+5 \n" ); document.write( "L=20 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "300=15*20 \n" ); document.write( "300=300 \n" ); document.write( " |