document.write( "Question 428715: whats the function for each, find f(-5), f(-3), f(1/2), and f(4).\r
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document.write( "f(h)= -6h-2/3 \n" );
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Algebra.Com's Answer #297930 by stanbon(75887) ![]() You can put this solution on YOUR website! find f(-5), f(-3), f(1/2), and f(4) \n" ); document.write( "if f(h)= -6h-2/3 \n" ); document.write( "---- \n" ); document.write( "f(-5)= -6*-5 -2/3 \n" ); document.write( "= 30-(2/3) \n" ); document.write( "= 29 1/3 \n" ); document.write( "----------------- \n" ); document.write( "f(-3) = -6*-3 -(2/3) \n" ); document.write( "18-(2/3) \n" ); document.write( "= 17 1/3 \n" ); document.write( "----------------------- \n" ); document.write( "f(1/2) = -6*(1/2)-(2/3) \n" ); document.write( "= -3-(2/3) \n" ); document.write( "= (-9/3)-(2/3) \n" ); document.write( "= -11/3 \n" ); document.write( "--------------- \n" ); document.write( "f(4)= -6(4)-(2/3) \n" ); document.write( "= -24-(2/3) \n" ); document.write( "--- \n" ); document.write( "= (-72/3)-(2/3) \n" ); document.write( "--- \n" ); document.write( "= -74/3 \n" ); document.write( "======== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |