document.write( "Question 428673: 3y^2+5y=-2 \n" ); document.write( "
Algebra.Com's Answer #297914 by Gogonati(855)\"\" \"About 
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Solution:First we set the equation to zero:\r
\n" ); document.write( "\n" ); document.write( "\"3y%5E2%2B5y%2B2=0\" Using the Quadratic Formula we have:\r
\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2B-sqrt%2825-24%29%29%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2B-sqrt%281%29%29%2F6\", y=-5+1/3=-4/6=-2/3 and y=-5-1/6=-6/6=-1\r
\n" ); document.write( "\n" ); document.write( "Answer: The solution set is {-1,-2/3}
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