document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428650>Question 428650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one leg of a triangle is 7 ft longer than other leg. The length of the hypothenuse is 13ft. Find the lengths of the other two sides. \r<BR>\n" );
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document.write( "How would I set this up? I know its a² + b² = c² but I don't know which is which or how to go about setting it up to solve.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297906 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x ft the length of one leg. Then the other leg will be: x+7 ft. Since the hypotenuse is 13 ft, we write the Pythagorean theorem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%28x%2B7%29%5E2=13%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B%28x%2B7%29%5E2=13%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2Bx%5E2%2B14x%2B7%5E2=13%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2Bx%5E2%2B14x%2B7%5E2=13%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Set the equation to zero.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B14x-120=0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B14x-120=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, divide both sides by 2\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B7x-60=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B7x-60=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, factor the equation. \r<BR>\n" );
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document.write( " (x-5)(x+12)=0 => x-5=0 => x=5 and x+12=0 => x=-12 Since the length is always positive, the root -12 is rejected.\r<BR>\n" );
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document.write( "Answer: The short leg is 5 ft and the long one is 5+7=12 ft. </SPAN>\n" );
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