document.write( "Question 428650: one leg of a triangle is 7 ft longer than other leg. The length of the hypothenuse is 13ft. Find the lengths of the other two sides. \r
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Algebra.Com's Answer #297902 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "one leg of a triangle is 7 ft longer than other leg
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document.write( "Let x and (x+7)represent th elengths of the two legs respectively
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document.write( " a² + b² = c² 
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document.write( " x^2 + (x+7)^2 = 13^2
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document.write( " 2x^2 + 14x -120 = 0
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document.write( " x^2 + 7x - 60 = 0
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document.write( "(x + 12)(x-5) = 0
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document.write( "(x + 12)=0  x = 12  |tossing out negative solution for length
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document.write( " (x-5) = 0
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document.write( "  x = 5, the other side is 12  (5+7)\r
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document.write( " CHECKING our Answer***
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document.write( " 25 + 144 = 169 = 13^2 \n" );
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