document.write( "Question 428647: In a right triangle, the shortest leg is two inches less than the longer leg. The hypotenuse is two inches longer than the longer leg. Find the measures of the sides of the right triangle.
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Algebra.Com's Answer #297896 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "the shortest leg is two inches less than the longer leg
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document.write( "The hypotenuse is two inches longer than the longer leg
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document.write( "Let x-2, x, x+2 represent the legs and hpotenuse respectively
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document.write( "Applying the Pythagorean Theorem
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document.write( "(x-2)^2 + x^2 = (x+2)^2 
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document.write( " x^2 - 4x+4 + x^2 = x^2 + 4x + 4
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document.write( "    x^2 - 8x = 0
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document.write( "  x(x-8) = 0
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document.write( "     x = 8in, the other leg is 6in and the hyportenuse is 10in\r
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document.write( "CHECKING our Answer***
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document.write( "6in^2 + 8in^2 = 36in^2 + 64in^2 = 100in^2 = 10in^2 \n" );
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