document.write( "Question 44917: a small corporation borrowed $500,000 to expand its product line. Some of
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document.write( "the money was borrowed at 9%, some at 10% and some at 12%. How much was
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document.write( "borrowed at each rate if the annual interest was $52, 000 and the amount
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document.write( "borrowed at 10% was two and a half times the amount borrowed at 9%? \n" );
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Algebra.Com's Answer #29788 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! x = amount borrowed at 9% \n" ); document.write( "y = amount borrowed at 10% \n" ); document.write( "z = amount borrowed at 12% \n" ); document.write( " \n" ); document.write( "Annual interest charged at 9% = \n" ); document.write( "Annual interest charged at 10% = \n" ); document.write( "Annual interest charged at 12% = \n" ); document.write( "Total annual interest = 52000 \n" ); document.write( " \n" ); document.write( "according to problem, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "also, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply both sides of this equation by (-.12) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and the other equation was \n" ); document.write( " \n" ); document.write( "add these equations \n" ); document.write( " \n" ); document.write( "divide both sides by (-.08) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "check \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |