document.write( "Question 428486: mr. sharma ivested a total of 30,000 in two ventures for a year. the annual return from one of them is 8% and the other paid 10.5% for the year. he recieved a total income of 2250 from both. how much did he invest at each rate???\r
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document.write( "i need help solving this problem. \n" );
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Algebra.Com's Answer #297829 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Below an interest of Rs 2400 one investment becomes negative. not possible\r \n" ); document.write( "\n" ); document.write( "I have worked with Rs. 2550. as interest. instead of Rs 2250. \r \n" ); document.write( "\n" ); document.write( "Part I 8.00% per annum \n" ); document.write( "Part II 10.50% per annum \n" ); document.write( " \n" ); document.write( "x + y 30000 ------------------------1 \n" ); document.write( "8.00%x+10.50%y= Rs2,550.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "8x+10.5y =Rs255,000.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -8 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-8x-8y= -240000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "2.5y=$15,000.00 \n" ); document.write( " \n" ); document.write( "divide by 2.5 \n" ); document.write( " \n" ); document.write( "y=Rs.6,000.00 investment at at 10.5% \n" ); document.write( "Balance Rs.24,000.00 investment at 8% \n" ); document.write( " \n" ); document.write( " |