document.write( "Question 427792: The sum of a number and four times its reciprocal is 29/5.Find the number \n" ); document.write( "
Algebra.Com's Answer #297813 by eggsarecool(46)\"\" \"About 
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The sum of a number and four times its reciprocal is 29/5.Find the number \r
\n" ); document.write( "\n" ); document.write( "Let's call the number n.\r
\n" ); document.write( "\n" ); document.write( "The reciprocal would be \"1%2Fn\"\r
\n" ); document.write( "\n" ); document.write( "So the formula should look like.
\n" ); document.write( "\"n%2B4%2A%281%2Fn%29=29%2F5\"
\n" ); document.write( "now multiply every term on both sides by n, the \"1%2Fn\" in the \"4%2A%281%2Fn%29\" will cancel to become 1, leaving you with 4*1=4
\n" ); document.write( "\"n%5E2%2B4=%2829%2F5%29%2An\" multiply both sides by 5.
\n" ); document.write( "\"5n%5E2%2B20=29n\" subtract \"29n\" from both sides
\n" ); document.write( "\"5n%5E2-29n%2B20=0\" now you have a solvable quadratic equation, that factors into.
\n" ); document.write( "\"%285n-4%29%28n-5%29=0\"
\n" ); document.write( "So \"n=5\" or \"5n-4=0\" -> \"5n=4\" divide both sides by 5 \"n=5%2F4\"
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