document.write( "Question 428435: What's are the steps to deriving a quadratic formula, and can you explain how you did each step? \n" ); document.write( "
Algebra.Com's Answer #297796 by richard1234(7193)\"\" \"About 
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Start with the general form \"ax%5E2+%2B+bx+%2B+c+=+0\" and divide both sides by \"a\" to get \"x%5E2+%2B+%28b%2Fa%29x+%2B+%28c%2Fa%29+=+0\". To complete the square, we want the constant term to be \"%28b%2F2a%29%5E2\" or \"b%5E2%2F4a%5E2\" so we add \"b%5E2%2F4a%5E2+-+c%2Fa\" to both sides to get\r
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\n" ); document.write( "\n" ); document.write( ". The left side factors to \"%28x+-+b%2F2a%29%5E2\" so the equation is equivalent to\r
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\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+b%2F2a%29%5E2+=+%28b%5E2+-+4ac%29%2F4a%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Taking square root of both sides,\r
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\n" ); document.write( "\n" ); document.write( "\"x+%2B+b%2F2a+=+%280+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F2a\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F2a\" <-- and there's the quadratic formula.
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