document.write( "Question 428386: how much pure gold (24k) must be mixed with 60% gold to get 20 grams of 75% gold \n" ); document.write( "

Algebra.Com's Answer #297786 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
......... percent ---------------- quantity
\n" ); document.write( "24k 100---------------- x gms
\n" ); document.write( "Gold 60% 60---------------- 20-x gms
\n" ); document.write( "Total 75.00% ---------------- 20
\n" ); document.write( "100x+60(20-x)=75*20
\n" ); document.write( "100x+1200-60x=1500
\n" ); document.write( "100x-60x =1500-1200
\n" ); document.write( "40x=300
\n" ); document.write( "/40
\n" ); document.write( "x=7.5gms
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "

\n" );