document.write( "Question 428350: find 3 consecutive positive integers such that the product of the first and third, minus the second, is 1 more than 7 times the third \n" ); document.write( "
Algebra.Com's Answer #297765 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "three consecutive integers are x, x+1 and x+2.\r
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\n" ); document.write( "\n" ); document.write( "x*(x+2) - (x+1) = 1+ 7(x+2)\r
\n" ); document.write( "\n" ); document.write( "=> x^2 + 2x - x -1 = 1 + 7x + 14\r
\n" ); document.write( "\n" ); document.write( "=> x^2 -6x -16 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x^2 -8x + 2x -16 = 0\r
\n" ); document.write( "\n" ); document.write( "=> x(x-8) +2(x -8) = 0\r
\n" ); document.write( "\n" ); document.write( "=> (x+2)(x-8) =0\r
\n" ); document.write( "\n" ); document.write( "so, x=8 and x = -2 (not positive integer)\r
\n" ); document.write( "\n" ); document.write( "numbers are 8, 9 and 10.\r
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