document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428258>Question 428258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer wants to enclose two adjacent rectangular regions next to a river, one sheep and one for cattle. No fencing is needed next to the river, but fencing must be used to divide the sheep pen for the cattle pen. The farmer has 60 meters of fencing in all. What is the area of the largest region that can be enclosed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297750 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer wants to enclose two adjacent rectangular regions next to a river, one sheep and one for cattle. No fencing is needed next to the river, but fencing must be used to divide the sheep pen for the cattle pen. The farmer has 60 meters of fencing in all. What is the area of the largest region that can be enclosed?<BR>\n" );
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document.write( "From the information given, we will need 3 widths and 1 length<BR>\n" );
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document.write( "L + 3W = 60<BR>\n" );
document.write( "L = (60-3W)<BR>\n" );
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document.write( "Area<BR>\n" );
document.write( "A = L*W<BR>\n" );
document.write( "Replace L with (60-3W)<BR>\n" );
document.write( "A = W(60-3W)<BR>\n" );
document.write( "A = -3W^2 + 60W<BR>\n" );
document.write( "max area occurs at the axis of symmetry, (x=-b/(2a)), in this equation a=-3, b=60<BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-60%29%2F%282%2A-3%29 ALIGN=MIDDLE  ALT=\"%28-60%29%2F%282%2A-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = + 10 meters is the width<BR>\n" );
document.write( "Find the Length<BR>\n" );
document.write( "60 - 3(10) = 30 meters is the length<BR>\n" );
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document.write( "Max area: 30 * 10 = 300 sq/meters<BR>\n" );
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