document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428263>Question 428263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lois and clark, two elderly reporters are covering separate stories and have to travel in opposite directions. lois leaves the daily planet building at 0800 am<BR>\n" );
document.write( "and travels at 35 mph. clark leaves at 0815 and travels at 40 mph. at what time will they be 140 mi apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297733 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> they are traveling in opposite directions.\r<BR>\n" );
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document.write( "the total distance both of them have to travel is 140 miles.\r<BR>\n" );
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document.write( "since they are traveling in opposite directions, their miles traveled will be additive.\r<BR>\n" );
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document.write( "lois leave at 0800 and travels at 35 miles per hour.\r<BR>\n" );
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document.write( "clark leaves at 0815 and travels 40 miles per hour.\r<BR>\n" );
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document.write( "in 15 minutes, lois will have traveled 1/4 of an hour at 35 miles per hour for a distance of 8.75 miles.\r<BR>\n" );
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document.write( "since they are already 8.75 miles apart, they have a remaining 131.25 miles to travel in order to be a total of 140 miles apart.\r<BR>\n" );
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document.write( "the time they have to travel needs to be the same from 0815 on.\r<BR>\n" );
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document.write( "we'll call that T.\r<BR>\n" );
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document.write( "lois will be traveling for a total of 35 miles per hour for T hours.\r<BR>\n" );
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document.write( "clark will be traveling for a total of 40 miles per hour for the same T hours.\r<BR>\n" );
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document.write( "the formula to be used will be:\r<BR>\n" );
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document.write( "35 * T + 40 * T = 131.25 \r<BR>\n" );
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document.write( "combine like terms to get 75 * T = 131.75\r<BR>\n" );
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document.write( "divide both sides of the equation by 75 to get T = 131.75 / 75.\r<BR>\n" );
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document.write( "this makes T equal to 1.75 hours.\r<BR>\n" );
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document.write( "in 1.75 hours, lois will have traveled 35 * 1.75 equals 61.25 miles.\r<BR>\n" );
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document.write( "in 1.75 hours, clark will have traveled 40 * 1.75 equals 70 miles.\r<BR>\n" );
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document.write( "the total distance traveled is 131.25 miles.\r<BR>\n" );
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document.write( "since they were already 8.75 miles apart at 0815, then they are now 140 miles apart.\r<BR>\n" );
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document.write( "1.75 hours is equal to 1 hour and 45 minutes.\r<BR>\n" );
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document.write( "add 1 hour and 45 minutes to 8 hours and 15 minutes and you get 10 hours and 0 minutes which is equal to 1000 hours or 10:00 am.\r<BR>\n" );
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document.write( "a distance and time line would probably something look like this:\r<BR>\n" );
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document.write( "                                 0800  0815\r\n" );
document.write( "                                  A----->B\r\n" );
document.write( "                                    8.75\r\n" );
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document.write( "            1000                    0815                    1000\r\n" );
document.write( "       D<-------------------------A      B-------------------->C\r\n" );
document.write( "                      70 miles                  61.25 miles\r\n" );
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document.write( "At 0800 lois leaves point A and travels to point B for a distance of 8.75 miles.<BR>\n" );
document.write( "At 0815 Lois leaves point B and travels to point C for a distance of 61.25 miles.<BR>\n" );
document.write( "At 0815 Clark leaves point A and travles to point D for a distance of 70 miles.\r<BR>\n" );
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document.write( "Total distance traveled by Lois is 61.25 + 8.75 = 70 miles.<BR>\n" );
document.write( "Total distance traveled by Clark is 70 miles.<BR>\n" );
document.write( "Total distance between Lois and Clark is 140 miles.\r<BR>\n" );
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document.write( "Time traveled is .25 hours from 0800 to 0815 plus 1.75 hours from 0815 to 1000.\r<BR>\n" );
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document.write( "they are 140 miles apart at 1000 hours or 10:00 am.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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