document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428269>Question 428269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two automobiles leave the same location traveling in opposite directions. The blue car travels x mph; the red car travels y mph. How long will it be before the cars are 200 miles apart, if the red car is traveling 10 mph slower? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297720 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two automobiles leave the same location traveling in opposite directions. The blue car travels x mph; the red car travels y mph. How long will it be before the cars are 200 miles apart, if the red car is traveling 10 mph slower?<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "y = x-10 mph<BR>\n" );
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document.write( "The separation rate of the two cars is x+y or x+x-10 = 2x-10<BR>\n" );
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document.write( "time = distance/rate<BR>\n" );
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document.write( "time = 200/(2x-10) = 200/(2(x-5)) = 100/(x-5) hrs.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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