document.write( "Question 44910: factor each polynomial completely by factoring out any common factors and then factor by grouping. Do not combine like terms.
\n" ); document.write( "\"3a%5E3%2B3ab%5E2%2B2a%5E2b%2B2b%5E3\"
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Algebra.Com's Answer #29771 by Chris435435(8)\"\" \"About 
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I tried to factor out an a from the \"3a%5E3%2B3ab%5E2\" part of the expression
\n" ); document.write( "and a b from the remaining part of the expression. I was able to factor and a from the first expression because an a is common in each term of the expression. That is, there is an a and \"3a%5E3\" and an a in \"3ab%5E2\". \"3a%5E3\" and \"3ab%5E2\" are called \"terms\" of the \"expression\" \"3a%5E3%2B3ab%5E2\" Because they both have an a in them, I can take an a out. Similar reasoning with b takes place too. Using this reasoning, I obtained the expression.\r
\n" ); document.write( "\n" ); document.write( "\"a%283a%5E2%2B3b%5E2%29%2Bb%282a%5E2%2B2b%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "Now I just think of factor by grouping to be a special name for this type of factoring situation. However, it's the same exact idea as before. Treat \"a%5E2%283a%2B2b%29\" as one term and \"b%282a%5E2%2B2b%5E2%29\" as another term of the expression \"a%283a%5E2%2B3b%5E2%29+%2Bb%282a%5E2%2B2b%5E2%29\". Unfortunately, there isn't a common factor in either of these terms. So we will have to try another approach.\r
\n" ); document.write( "\n" ); document.write( "Let's start over. Let's try to rearrange the terms so that we can get some terms with a common factor between them. \r
\n" ); document.write( "\n" ); document.write( "\"3a%5E3%2B2a%5E2b%2B3ab%5E2%2B2b%5E3\" \r
\n" ); document.write( "\n" ); document.write( "Using similar reasoning to how I factored before I obtain:\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2%283a%2B2b%29%2Bb%5E2%283a%2B2b%29\"\r
\n" ); document.write( "\n" ); document.write( "There is a common factor between each term, that is (3a+2b) is the common factor. Thus, using factor by grouping I obtain the factored form:\r
\n" ); document.write( "\n" ); document.write( "\"%283a%2B2b%29%28a%5E2%2Bb%5E2%29\"
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