document.write( "Question 44910: factor each polynomial completely by factoring out any common factors and then factor by grouping. Do not combine like terms.
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Algebra.Com's Answer #29771 by Chris435435(8)![]() ![]() ![]() You can put this solution on YOUR website! I tried to factor out an a from the \n" ); document.write( "and a b from the remaining part of the expression. I was able to factor and a from the first expression because an a is common in each term of the expression. That is, there is an a and \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now I just think of factor by grouping to be a special name for this type of factoring situation. However, it's the same exact idea as before. Treat \n" ); document.write( "\n" ); document.write( "Let's start over. Let's try to rearrange the terms so that we can get some terms with a common factor between them. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using similar reasoning to how I factored before I obtain:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is a common factor between each term, that is (3a+2b) is the common factor. Thus, using factor by grouping I obtain the factored form:\r \n" ); document.write( "\n" ); document.write( " |