document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428215>Question 428215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you express 4^-3=1/64 in logarithmic form? When I did this question I got log base 4 of 64 equals -3. I just wanted to be sure I was doing it right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297697 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You're off a little<BR>\n" );
document.write( "You can take the log to base 4 of both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%284%2C+4%5E%28-3%29%29+=+log%284%2C+1%2F64%29+ ALIGN=MIDDLE  ALT=\"+log%284%2C+4%5E%28-3%29%29+=+log%284%2C+1%2F64%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-3+=+log%284%2C+1%2F64+%29 ALIGN=MIDDLE  ALT=\"+-3+=+log%284%2C+1%2F64+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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